sexta-feira, 27 de fevereiro de 2015

6° - Matemática

27/02/15

                Resolva:
a) log x2+2x+1 = log x+1
Obs.: Se logax = logay -> x=y
                      \         /
                       Iguais

X2+2x+1=x+1
X2+2x+1-1-x=0
X2+x=0      ->x=0
X(x+1)=0 /
                 \
                  ->x+1=0
                      x=-1